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\[ \sin A \cos B = \frac{1}{2}\left[ \sin(A-B)+\sin(A+B) \right] \]

\begin{align*} e^x & = 1 + x + \frac{x^2}{2} + \frac{x^3}{6} + \cdots \\ & = \sum_{n\geq 0} \frac{x^n}{n!} \end{align*}

$a^2 + b^2 = c^2$

\(1+2+\dots+n=\frac{n(n+1)}{2}\)

$\sqrt {x^2} $

$\frac{ \sqrt{ x } }{ y^{ 5 } }$